(a) For the nuclei^11_5 B and^11_6 C, determine the difference in binding energy
ID: 1613480 • Letter: #
Question
(a) For the nuclei^11_5 B and^11_6 C, determine the difference in binding energy per nucleon (in Mev). (Let the mass of a proton be 1.0078 u, the mass of a neutron be 1.0087 u, the mass of^11_5 B be 11.0093 u, and the mass of^11_6C be 11.0114 u.) (b) This difference in binding energy is due to which of the following? Greater proton repulsion for the^11_6 C nucleus Greater electron attraction for the^11_6 C atom Greater proton attraction for the^11_6 C nucleus Greater neutron repulsion for the^11_6 C nucleus. Greater neutron attraction for the^11_6 C nucleus Greater electron repulsion for the^11_6 C atomExplanation / Answer
(a) Binding of energy of 11B5 = Dmc^2
= (6mn +5mp -mB)c^2
= (6*1.0087 +5*1.0078 - 11.0093)uc^2
1uc^2 = 931.5 MeV
= (6*1.0087 +5*1.0078 - 11.0093)*931.5 Mev
BE= 76.28985 MeV
Binding energy of nucleon = 76.28985/11 = 6.93544 MeV
Binding of energy of 11C6 = Dmc^2
= (5mn +6mp -mB)c^2
= (5*1.0087 +6*1.0078 - 11.0114)uc^2
1uc^2 = 931.5 MeV
= (5*1.0087 +6*1.0078 - 11.0114)*931.5 Mev
BE= 73.49535 Mev
Binding energy of nucleon = 73.49535/11 = 6.6814 MeV
Difference in binding energy per nucloen = 6.93544 -6.6814
= 0.254 MeV
(b) greater proton repulsion for the 11C6 nucleus (1)
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