A 0.02 kg bullet traveling at 350 m/s hits a 3.0 kg copper plate at 25 degrees C
ID: 1613311 • Letter: A
Question
A 0.02 kg bullet traveling at 350 m/s hits a 3.0 kg copper plate at 25 degrees C and comes to a stop. If all of the bullet's energy is converted to heat that only the 3.0 kg of copper absorbs, what is the final temperature of the copper plate. The specific heat of lead: 390J/kg degrees C A 0.02 kg bullet traveling at 350 m/s hits a 3.0 kg copper plate at 25 degrees C and comes to a stop. If all of the bullet's energy is converted to heat that only the 3.0 kg of copper absorbs, what is the final temperature of the copper plate. The specific heat of lead: 390J/kg degrees CExplanation / Answer
kinetic energy of the bullet K = (1/2)*m*v^2
heat absorbed by lead Q = M*s*dt
all of the bullet's energy is converted to heat
Q = k
M*s*(tf - ti) = (1/2)*m*v^2
3*390*(tf-25) = (1/2)*0.02*350^2
tf = 26.05 degrees <<<<<--------------answer
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