A new element has been produced, called Volunteerium (Vo). This unstable isotope

Question

A new element has been produced, called Volunteerium (Vo). This unstable isotope has 104 protons and 163 neutrons. It decays by alpha emission to Nobelium (No). Answer the three questions below, using three significant figures. What is the atomic mass number (A) for the Nobelium that results from the decay of the Volunteerium? A = (Enter a whole number value.) Suppose that 112 micrograms of Vo are initially produced, after 6.00 seconds, there are 56.0 micrograms remaining. How long does it take (t_f) before there are only 14.0 micrograms remaining? t_f = s What is the decay constant (lambda) for Vo? lambda = s^-1

Explanation / Answer

(A) In alpha decay Atomic mass number is always decreased by 4 units.

and atomic mass number A= (number of electron + number of proton)

so the the atomic mass number of Nobelium is =(163+104)- 4= 263 ANS

(B)

Intially the V0 produced is 112 micrograms

after 1st half time priod it becomes =56 micrograms

after 2nd half time period = 28 micrograms

after 3rd half time period =14 micrograms

it takes 3half time to becomes 14 micrograms so

Total time requried =3×t1/2 = 3×6=18 sec ANS

(C)

we have

=0.693/ t1/2

= 0.693 / 6

= 0.1155 sec-1 ANS

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