If the voltage phasor is at a given instant pointing downward, the phasor for th

Question

If the voltage phasor is at a given instant pointing downward, the phasor for the current in the capacitive line points: to the left, to the right, upward, downward If the voltage phasor is at a given instant pointing downward, the phasor for the current in the inductive line points: to the left, to the right, upward, downward Find the rms current drawn from the AC source in a RLC parallel circuit if the rms current in the resistive line is 50 mA. the rms current in the capacitive line is 21 mA. and the rms current in the inductive line is 39 mA. 52 mA. 42.2 mA. 53.1 mA. 68 mA Find the phase angle between the voltage and the current in a RLC parallel circuit if the rms current in the resistive line is 50 mA. the rms current in the capacitive line is 21 mA, and the rim current in the inductive line is 39 mA -19.8 degree, 19.8 degree, 70.2 degree, -70.2 degree An AC source is connected 10 a RL, parallel circuit. The rim current in the resistive line is 40 mA, and the rms current in the inductive line is 30 mA. The rms current drawn from the AC source is: 10 mA. 25 mA, 50 mA. 70 MA

Explanation / Answer

8&9 ans

Given that

rms current in the resistance =50 mA

rms current in the capacitance =21mA

rms current in the inductance =39 mA

now we find the rms current in the ac circuit

the rms current Is=[50^2+(39-21)^2]^1/2=53.14 mA

now we find the phase angle voltage and current RLC parallel circuit

Phase angle=tan^-1[IL-Ic/IR]=tan^-1[39-21/50]=19.8 degree

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10 ans'

Given that

rms current in the resistance Ir=40mA

rms current in the inductance IL=30 mA

now we find the total rms current in the circuit

the total rms current I=[40^2+30^2]^1/2==25mA

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