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Ha The Expert TA l Human-i x a Secure https://usq40pa.theexpertta.com /common/TakeTu alAssignment aspx Horne work 13 Begin Date: 4/7/2017 10:00:00 AM Due Date: 4 21/2017 11:59:00 PM End Date: 4/22/2017 59:00 PM 10%) Problem 2: An object is located in air, 34 cm from the vertex of the concave surface of a block of glass (as vicwed from the air side of the surface). The surface radius of curvature is 13 cm. Use these indices of refraction: n 1.0 and glass Assignment Status Click here for 50% Part (a) Find the refraction image distance, in centimeters. Include its sign. detailed view Grade Summary 6,78 Potent 00% Problem Status 7 8 9 HovrF Submissions sin cos tan 1 Completed Altempts 4 5 6 2 Partial cotan0 asino per attemp) detailed view at ano aco Completed 4 Completed cosh() tanh0 cotanh() V() BACKSPACE DEL CLEAR Degrees Radians Completed Completed Completed Feed hack S tion per feedhack. 9 Partial 10 Completed Submission History Answer Hin Feedback olals 6,78 6,78 Total 50% Part (b) What is the magnification of the image? Include the magnification's sign to indicate the orientation of the image with respect to the object. 9:24 PMExplanation / Answer
a)
do = object distance = 34 cm
R = radius of curvature = 13 cm
nair = 1
nglass = 1.5
focal length is given as
1/f = (nglass /nair - 1) (- 2/R)
1/f = (1.5 - 1) (- 2/13)
f = - 13 cm
di = image distance
using the lens equation
1/di + 1/do = 1/f
1/di + 1/34 = 1/(-13)
di = - 9.4 cm
b)
magnification is given as
m = - di/do = - (-9.4)/34 = 0.28
the positive sign indicates that the image is upright with respect to the object
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