The magnitude of the electric field between the two circular parallel plates in

Question

The magnitude of the electric field between the two circular parallel plates in the figure below is E = 3.4 times 10^5 - (5.0 times 10^4 t), with E in volts per meter and t in seconds. At t = 0, E^vector is upward. The plate area is 2.8 times 10^-2 m^2. (a) For t greaterthanorequalto 0, what is the magnitude of the displacement current between the plates? (b) For t greaterthanorequalto 0, what is the direction (up or down) of the displacement current between the plates? up down (c) Is the direction of the induced magnetic field clockwise or counterclockwise in the figure? clockwise counterclockwise

Explanation / Answer

(a) E = 3.4*10^5 - 5*10^4*t

dE/dt = -5*10^4

A = 2.8*10^-2 m^2

displacement current id = eo*d(phi)/dt

phi = E.A

id = eo*A*dE/dt

id = -(8.85*10^-12*2.8*10^-2*5*10^4)

id = -1.24*10^-8 A

(b) down

(c) counterclockwise

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