004 (part 1 of 3) 10.0 points A rectangular loop of copper wire of re- sistance

Question

004 (part 1 of 3) 10.0 points A rectangular loop of copper wire of re- sistance R has width a and length b. The loop is stationary in a constant, uniform mag- netic field Bo, directed into the page as shown above B b n turns What is the net magnetic flux through the loop of wire? 1. a b 2. ab Bo 3. nab Bo Bo a b ab Bo 6. abn 005 (part 2 of 3) 10.0 points For The 4, a F 9 m b 1 m, and B 6 T what is the induced emfin the loop of wire? 1. & 0 V 3. E 560 A. E 3 216 V 5. E 1200 6. E 4032 006 (part 3 of 3) 10.0 points What is the net magnetic force on the loop of wire? 1. F ON 2. F 72 3. F 189 5. F 13.5 N 6. F 2.57143

Explanation / Answer

Part 1 of 3 - The magnetic flux, = magnetic field x area = B0(nA) = nB0ab

Part 2 of 3 - The magnetic flux, = nB0ab

Hence induced e.m.f., e = -d/dt = 0 V.

Part 3 of 3 – As induced e.m.f = 0

So induced current, I = 0

Hence magnetic force, F = 0 N.

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