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x C The Figure Shows An ovi x Violoome, Mina Blackb x C Secure https student/mainfruni wiley PLUS: NywileyFIUS Wiley PLUS Halliday, Fundamentals of Physics, 10e ty Phy versity Physi Assignment Gradebook Home Read, Study & Practice Assignment Open Assignment FULL scREEN PRINTER VERSION BACx NEXT GNMENT RESOUR Chapter 11, Prob 054 The figure shows an overhead view of a ring that can notate about its center like a memr go round. Its outer radius R2 is 0.8 m, its inner radius R1 is R2/2, its mass M is 8.8 kg, and the mass of the bars at its center is negligible. It initially rotates at an angular speed of 6.2 rad/s with a cat of mass m M4 on its outer edge, at radius R2. By how much does the cat increase the kinetic energy of the cat-ring system if the cat crawls to the inner edge, at radius R the tolerance is +/-7% SHOW HINT GO TUTORIAL LINK To SAMPLEPROGLEM LINK TO SAMPLE PROALEM LINK To SAMPLE PRORLEN VIDEO MENI-LECTURE Results by study objecti Question Attempts: Unlimited ISAVEFORLATER I SRMMIT ANSWER All Rights Reserved. A Division of 4.22.29 535 PM e a Ask me anything /7/201Explanation / Answer
M.I of the ring I1
M.I of the cat initially I2
MI of the cat finally I3
Initial angular momentum (I1+ I2) i
Final angular momentum (I1+ I3) f
(I1+ I3) f = (I1+ I2) i
Initial k.e = 0.5 (I1+ I2) i²
Final k.e = 0.5 (I1+ I3) f²
Increase in energy = 0.5 (I1+ I3) f² - 0.5 (I1+ I2) i²
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I1 = 0.5 M (R1² + R2²) = (5/8) M R2²
I2 = mR2² = (M/4) R2²
I1 + I2 = (5/8) M R2² + (M/4) R2 ² = (7/8) M R2² = (7/8) 8.8*0.8² =4.928 kg.m²
I1 + I3 = (5/8) M R2² + (M/4) (R2/2) ² = (11/16) M R2² = (11/16) 8.8*0.8² = 3.872 kg.m²
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f = (I1+ I2) i/ (I1+ I3) = [(7/8)/ (11/16)] *6.2 = 7.89rad/s
Increase in energy = 0.5 {(I1+ I3) f² - (I1+ I2) i²}
Increase in energy = 0.5 {3.872*7.89² -4.928*6.2²} = 25.80 J
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