As shown in the figure, two long, straight current-carrying wires (1 and 2) are

Question

As shown in the figure, two long, straight current-carrying wires (1 and 2) are attached at right angles to a board by wire brackets. The current in wire 1 is 7.57 A in the positive y direction and the current in wire 2 is 5.00 A in the positive x direction. The points A and B are a distancer = 0.200 m from both wires.

(a) How does the magnitude of the net magnetic field at point A compare to the magnitude of the net magnetic field at point B?
       BA is greater than BB
       BA is equal to BB
       BA is less than BB
(b) Determine the magnitude of the net magnetic field at points A and B.
     Point A _________T
     Point B _________ T

Explanation / Answer

For a straight current-carrying wire,
B dL = (µo)(I)
B(2r) = (µo)(I)
B = (µo)(I) / (2r)

Using right-hand rule, the magnetic field components due to the separate wires will get subtracted from each other at both points A and B. Since the distances from the wires are the same, the magnitude of the magnetic field will be the same at A and B, though in opposite directions.

a) BA is equal to BB

b)

Bv = (1.257e-6 N/A²)(7.57 A) / (2(0.2 m))
Bv = 7.576 e-6 T

BH = (1.257e-6 N/A²)(5 A) / (2(0.2 m))
BH = 5 e-6 T

7.576 e-6 T - 5 e-6 T = 2.576 e-6 T or 2.576 µT

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