2.The drawing shows a coin resting on the bottom of a beaker filled with an unkn

Question

2.The drawing shows a coin resting on the bottom of a beaker filled with an unknown liquid. A ray of light from the coin travels to the surface of the liquid and is refracted as it enters into the air. A person sees the ray as it skims just above the surface of the liquid. How fast is the light traveling in the liquid?

3.

The drawing shows a rectangular block of glass (n = 1.52) surrounded by a liquid with n = 1.73. A ray of light is incident on the glass at point A with a 30.0° angle of incidence. At what angle does the ray leave the glass at point B?

Explanation / Answer

1)

From your other posting I see where y = 6.0cm

Therefore the incidence angle (with respect to the normal) = arctans(x/y) = arctan(5/6) = 39.8o

Now the refracted angle here is 90o

so n1*sin(39.8) = 1.0

so n1 = 1.0/sin(39.8) = 1.562

Since n = c/v we have v = c/n = 3.00x10^8m/s/1.562 = 1.92x10^8m/s

2)

Using snell’s law

          n1sin1 = n2sin2

            (n1 / n2) sin1 = sin2

        sin2 = (1.73/1.52)sin(30) = 0.569

                2 = 34.680

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