The thin glass shell shown in the figure (Figure 1) has a spherical shape with a
ID: 1603757 • Letter: T
Question
The thin glass shell shown in the figure (Figure 1) has a spherical shape with a radius of curvature of 11.5 cm , and both of its surfaces can act as mirrors. A seed 3.30 mm high is placed 15.0 cm from the center of the mirror along the optic axis, as shown in the figure.
Part A
Calculate the location of the image of this seed.
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Part B
Calculate the height of the image of this seed.
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Part C
Suppose now that the shell is reversed. Find the location of the seed's image.
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Part D
Find the height of the seed's image.
s= cmExplanation / Answer
R = 11.5 cm , y = 3.3 mm , s = 15 cm
pART A:
from mirror formula:
2/R = 1/s +1/s'
2/11.5 = 1/15 +1/s'
s' = 9.32 cm
Part B:
lateral magnification
y'/y = s'/s
y'/3.3 = 9.32/15
y' = 2.05 mm
Part C: R = -11.5 cm
from mirror formula:
2/R = 1/s +1/s'
-2/11.5 = 1/15 +1/s'
s' = -4.16 cm
Part D:
lateral magnification
y'/y = s'/s
y'/3.3 = 4.16/15
y' = 0.915 mm
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