cCopyright 2016 Prof Raymond S. Robinson All rights reserved, no part o examinat

Question

cCopyright 2016 Prof Raymond S. Robinson All rights reserved, no part o examination mary be reproduced in any form or by any means without written permission L Two fixed point charges, q +2.0HC and qz -.8.0HC, exert an electro force ofattraction of magnitude 500 Non one another. What is their separation in m? (a 169 x 10 20 x 10 (e) 6.01 x (c) 8.30 x d) 2.08 2, Two fixed point charges, q +2.0wC and qz st.8.0uc, exert an electrostatic force of attraction of magnitude 500 N on one another How many excess electrons are on charge q:? 1.69 x 10 (b) 4.99 x 10 (c) 8.30 x 10s (d) 2.08 x e) 6.01 x 4. Four point charges, qu +2.50uc, q: 50HC, q +750HC and qu 5,50HC, are arranged in a plane square measuring 0.25 m on a side, What is the electric polential at the center of the square in Volts? e) 601 x 10 .20 x 10' (c) 1.09 x 10s (d) 1.53 x 10 A parallel plate capacitor has a potential difference of 100 Volts across the plates and a gap between the plates of2.50 mm. What is the electric field in Volts per meter in the center, far from any edge effects? (a) 4.00 x 10 b) 5.00 x 10" d) 2.50x 10' (e) 3.33 x 10' -a and the other 6. Two point charges are fixed on the x axis Each has a positive charge g One i is atx +a. At the origin, which one of the following is true? (a) E 0 and V 0 (b) E-0 and V q'O4xc. a) (c) E-(24/4rce i and V-0 (e) E se 0 and V 2 4xco a) 7. What is the acceleration of an electron in S units placed at a point where the electric field is E 5.90 x 10 Nicj (a) zero (c) 10 04 x 10 j of outer radius 0,17 m and with a total charge of5 x 10" C 8. Consider a thin sphe distributed uniform gn its sudace. Calculate the electric potential inside at a point 0.08s m from the center in Volts, 132 c) 2.64 x 10 6,6 10 (d) 8.30 x 1 9 The one-dimensional free on a proton is shown as a function of position the point that could possibly be a point of stable equilibrium for the proton (a) A b) (c) C (d) D (e) E Charges tQ and-Q are arranged at the comers of a square as shown. When the electric field magnitude E and the electric potential v are determined at P, the center of the square, we find that d (a) E and V 0 (b) E 0 and V 0 d) E 00 and V

Explanation / Answer

here,

1)

q1 = 2 uC = 2 * 10^-6 C

q2 = - 8 uC = - 8 * 10^-6 C

let the sepration between the charges be r

F = k * q1 * q2 /r^2

500 = 9 * 10^9 * 2 * 10^-6 * 8 * 10^-6 /r^2

r = 1.69 * 10^-2 m

the sepration between the charges is a) 1.69 * 10^-2 m

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