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View History Bookmarks People Window Help Texas Southern University Hw4: Capacitance and Dielect x D www.webassign.net/web/Student/Assignment-Responsesllast?dep 15675518 Neea Help Read Watch It My Notes o Ask Your Teacher O -4 points serPSET9 26 P009 MI An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm separated by a distance of 1.90 mm. A 25.0.v potential difference is applied to these plates. (a) Calculate the electric field between the plates. KVIm (b) Calculate the surface charge density. nc/m2 (c) Calculate the capacitance. (d) Calculate the charge on each plate. Need Help? Read t L Master it

Explanation / Answer

(a) By +/- = Q/A & E = /
=>E = Q/A
=>E = V/d
=>E = 25/[1.90 x 10^-3]
=>E = 13157.8347 Volt/m
=>E = 13.157 kV/m
(b) By C = A/d
=>C = [8.85 x 10^-12 x 7.60 x 10^-4]/[1.90 x 10^-3]
=>C = 3.54 x 10^-12 F
=>C = 3.54 pF
(c) By V = Qd/A
=>Q = VA/d
=>Q = [25 x 8.85 x 10^-12 x 7.60 x 10^-4]/[1.90 x 10^-3]
=>Q = 8.85 x 10^-12 C
=>Q = 8.85 pC

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