A meter stick made from a uniform-density material rests on a fulcrum positioned

Question

A meter stick made from a uniform-density material rests on a fulcrum positioned precisely at its middle. If a box of mass m = 3 kg Is suspended from the right end of the meter stick, the system would not be in equilibrium. Where and how could a force be applied to keep the system in equilibrium? (For ease of calculation, consider g = 10 N/kg.) A 30-N downward force at 40-cmmark A 15-N upward force at the 20-cm mark. A 50-N downward force at the 3-cm mark A 75-N upward force at the 70-cm mark A 60-N downward force at the 0-cm mark (the left end of the stick).

Explanation / Answer

Weight of box W = 3*10 = 30 N

A force has to be applied in such a way so that net torque is 0.

torque due to box,

M1 = 30*0.5 = 15N*m (downword)

torque created by another force should be equal to 15 N*m.

which in only posible for option D.

75*(0.70 - 0.50) = 15 N*m

so, the Answer is 75 N upward force at 70 cm mark.

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