o 0/2 points I Previous Answers SercP105 P.057 A 1.50 x 10 -kg car starts from r

Question

o 0/2 points I Previous Answers SercP105 P.057 A 1.50 x 10 -kg car starts from rest and accelerates uniformly to 18.3 in 12.3 air resistance remains constant at 400 N during this time. m/s s.Assume that (a) Find the average power developed by the engine. Your response differs significantly from the correct answer Rework your solution from the beginning and check each step carefully. hp (b) Find the instantaneous power output of the engine at t al 12.3 s, just before the car stops accelerating hp Need Help? Read Submit Assignment Save Assignment Progress Home My Assignments Extension Requesr 40 10072017 Advanced Inntructional Systems Inc Alnghts reserved NI OM

Explanation / Answer

Given: M =1.5×103 kg

Velocity change = 18.3 m/s

Time of velocity change= 12.3 s

Net acceleration of car can be find out as:

Net acceleration= 18.3/12.3= 1.49 m/s2

Net force acting on car= ma = (1.5×103)(1.49)= 2235 N

Force exerted by engine on car = 400 N+ 2235 N = 2635 N

Average velocity of car during 12.3 s = 18.3/2 = 9.15 m/s

a) Average power = F× Vavg= 2635×9.15= 24,110.25 W

b)Instantaneous power at t=12.3 s

P=F×V = 2635×18.3 = 48,220.5 W

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