Please correctly answer A and B, then explain how you got the answer. I have alr

Question

Please correctly answer A and B, then explain how you got the answer. I have already wasted several questions on Chegg trying to find the right answer for this question.

In the figure below, the hanging object has a mass of m1 0.445 kg; the sliding block has a mass of m2 0.885 kg; and the pulley is a hollow cylinder with a mass of 0.350 kg, an inner radius of R1 0.0200 m, and an outer radius of R2 0.030 0 m. Assume the mass of the spokes is negligible. The coefficient of kinetic friction between the block and the horizontal surface is puk 0.250. The pulley turns without friction on its axle. The light cord does not stretch and does not slip on the pulley. The block has a velocity of Vi 0.820 m/s toward the pulley when it passes a reference point on the table m1 (a) Use energy methods to predict its speed after it has moved to a second point, 0.700 m away m/s (b) Find the angular speed of the pulley at the same moment. rad/s

Explanation / Answer

f = uk N2 = uk m2 g = 0.250 x 0.885 x 9.8 = 2.17 N

Applyng energy conservation,

Work done by all forces = change in KE

m1 g h - f h = m1 v^2 /2 + m2 v^2 /2 + I w^2 /2 - m1 vi^2 /2 - m2 vi^2 / 2 - I wi^2 /2

I = M (R1^2 + R2^2) /2 = 0.350 (0.02^2 + 0.03^2) /2 = 2.275 x 10^-4 kg m^2

(0.445 x 9.8 x 0.7) - (2,17 x 0.7) = (0.445 + 0.885) v^2 /2 - ( 2.275 x 10^-4) ( v / 0.03)^2 / 2 - (0.445 + 0.885) (0.82^2)/2 - (2.275 x 10^-4) (.82 / 0.03)^2 / 2

3.0527 - 1.519 = 0.665 v^2 + 0.126 v^2 - 0.447 - 0.085

v = 1.616 m/s ..........Ans

(B) w = v / r = 1.616 / 0.03 = 53.9 rad/s

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