NUMBER 5 and 6 Following Question 1, the magnitude of the net force on q_1 is A.
ID: 1602021 • Letter: N
Question
NUMBER 5 and 6 Following Question 1, the magnitude of the net force on q_1 is A. -1910 N B. 1910 N C. -744 N D. 744 N Point P is midway between a -8.0 mu C and a 5.8 mu C charge 8.0 cm apart. The electric field at P points A. left B. right C. up D. down Following Question 4, the magnitude of the electric field at P is A. 7.76 times 10^7 N B. 7.76 times 10^7 N/C C. -7.76 times 10^7 N D. -7.76 times 10^7 N/C Following Question 4 and taking V=0 at infinity, the electric potential at P is A. -4.94 times 10^5 V B. 4.94 times 10^5 V C. -3.10 times 10^6 V D. 3.10 times 10^6 VExplanation / Answer
From the given question,
5. Magnitude of electric field at P is E1 + E2
=k q1/r12 + k q2/r22
=(9 x 109 x 8 x 10-6 )/ (0.04)2+ (9 x 109 x 5.8 x 10-6 )/(0.04)2
=9 x 109 / (0.04)2 [ 8 x 10-6 + 5.8 x 10-6 ]
=77625000 N/C
=7.76 X 107 N/C
6. electric potential at P is V1 - V2
=k q1/r1 - k q2/r2
=(9 x 109 x 5.8 x 10-6 )/ (0.04) - (9 x 109 x 8 x 10-6 )/(0.04)
=9 x 109 / (0.04)[ 5.8 x 10-6 - 8 x 10-6 ]
= -495000V
=-4.95 x 105 V
=77625000 N/C
=7.76 X 107 N/C
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