A particle of charge 26 mu C and mass 1.1 times 10^-15 kg moves at a speed of 20

Question

A particle of charge 26 mu C and mass 1.1 times 10^-15 kg moves at a speed of 2025 m/s, and its velocity vector lies in the x - y plane. There is a magnetic field of magnitude 0.90 T along the +z direction. The magnetic force on the particle causes the particle to move in a circle that lies in the x - y plane. (a) Find the radius of this circle. (b) Find the period of the motion. (c) If the particle is moving parallel to +y at t = 0, is the circular motion clockwise or is it counterclockwise as viewed from along the +z axis? clockwise counterclockwise

Explanation / Answer

balancing forces,

a)mv^2/r = qvB

or r=mv/qB

= (1.1*10^-15*2025)/(26*10^-6*0.90)

= 9.52*10^-8 m

b) w = v/r

T+2pi/w

= 2pi*r/v

= (2*3.14*(9.52*10^-8))/2025

= 2.95*10^-10 s

c)clockwise,

since jXk=i

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