iPad 5:40 PM e edugen.wileyplus. com Assignment Gradebook tice ment FULL SCREEN

Question

iPad 5:40 PM e edugen.wileyplus. com Assignment Gradebook tice ment FULL SCREEN PRINTER VERSION BACK NEXT Chapter 21 Problem 59 Two long, straight wires are separated by 0.120 m. The wires carry currents of 8.9 A in opposite directions, as the drawing indicates. Find the magnitude of the net magnetic field at the points labeled (a) A and (b) B. 0,030 m 0,060 m (a) Number units (b) Number Click if you would like to show work for this question Open Show Work By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your Question Attempts: o of 4 used SAVE FOR LATER SUBMIT ANSwER Earn Maximum Points available only if you answer this question correctly in four attempts or less. Copyright 2000-2017 by John Wiley & Sons, Inc. or related companies. All rights reserved

Explanation / Answer

a. At point A: B1 is up and B2 is down, so we subtract them to
get the net field.

We have
B1 = µ0I1/(2d1) = µ0(8.9 A)/[2(0.030 m)] = 5.9333*10^-5
B2 = µ0I2/(2d2) = µ0(8.9 A)/[2(0.150 m)] = 1.1866*10^-5

So the net field at point A is   
BA = B1 B2 = 4.8667 10^-5 T

b. At point B: B1 and B2 are both down so we add the two.
We have

B1 = µ0(8.9 A)/[2(0.060 m)] = 2.966*10^-5
B2 = µ0(8.9 A)/[2(0.060 m)]

So the net field at point B is
BB = B1 + B2 = 5.932* 10-^5 T

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.