The experiment you did in lab is repeated, using a uniform metal bar that is 80.

Question

The experiment you did in lab is repeated, using a uniform metal bar that is 80.0 cm long instead of the meterstick. Since the bar is uniform, its center of gravity is at its center. The new experiment uses different hooks for hanging the masses from the bar, with m_hook = 5.0 g. As in the experiment you did in lab, x_1 = 5.00 cm, m_1 = 300.0 g, and x_p = 25.0 cm. In the new experiment, you make the same measurements as in your lab and plot x versus 1/m_2 + m_hook. The line that is the best fit to your data has slope 3800 cm middot g. What is the mass of the bar?

Explanation / Answer

Answer :-

Given Data:-

m1 = 300 g ,

mhook = 5 g

xp =25 cm

K = 3800 cm*g

L =80 cm

we have to calculate the mass of the bar.

by using simple formula we can get a mass of the bar

M = (m1+mhook) (Xp) - (K) / (Xm -Xp)

put the values in above formula

= (300 g +5g )* ( 25 cm ) - 3800 cm*g / (40cm -25 cm )

M = 255 g.

Hence the mass of the bar is 255 g.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.