An artist working on a piece of metal in his forging studio plunges the hot meta

Question

An artist working on a piece of metal in his forging studio plunges the hot metal into oil in order to harden it. The metal piece has a mass of 56 kg and its specific heat is 0.1027 kcal/(kg · °C). He uses 810 kg of oil at 35°C. The specific heat of oil is 0.7167 kcal/(kg · °C). Once the metal is immersed in the oil, the temperature reaches an equilibrium value of 41°C. How hot was the forged metal piece just before he plunged it into the oil? °C An artist working on a piece of metal in his forging studio plunges the hot metal into oil in order to harden it. The metal piece has a mass of 56 kg and its specific heat is 0.1027 kcal/(kg · °C). He uses 810 kg of oil at 35°C. The specific heat of oil is 0.7167 kcal/(kg · °C). Once the metal is immersed in the oil, the temperature reaches an equilibrium value of 41°C. How hot was the forged metal piece just before he plunged it into the oil? °C An artist working on a piece of metal in his forging studio plunges the hot metal into oil in order to harden it. The metal piece has a mass of 56 kg and its specific heat is 0.1027 kcal/(kg · °C). He uses 810 kg of oil at 35°C. The specific heat of oil is 0.7167 kcal/(kg · °C). Once the metal is immersed in the oil, the temperature reaches an equilibrium value of 41°C. How hot was the forged metal piece just before he plunged it into the oil? °C

Explanation / Answer

using the principle of calorimetry

heat lost by the piece of metal = Heat gained by the oil

m_m*S_m*dT1 = m_oil*S_oil*dT2

56*0.1027*(T-41) = 810*0.7167*(41-35)

T = 646.64 deg C

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