Gasoline expands and contracts with changes in temperature. To eliminate mass in
ID: 1600490 • Letter: G
Question
Gasoline expands and contracts with changes in temperature. To eliminate mass inequities caused by changes in volume due to temperature variations, a selling volume of gasoline in Canada is adjusted to the volume it would occupy if it were measured at 15.0 degree C. The density of gasoline is 719 kg/m^3 at 15.0 degree C. The average coefficient of volume expansion for gasoline is 9.60 times 10^-4 (degree C)^-1. Consider 50.0 liters of gasoline at 15.0 degree C. Calculate its new volume when the temperature decreases to -25.0 degree C in a very cold day. Calculate the density of gasoline at -25.0 degree C If a pump was not temperature compensated, how much more gasoline would you get if you bought 50.0 liters of gasoline at -25 degree C rather than at 15.0 degree C from this pump? Express your answer in kilograms.Explanation / Answer
a)
m=15*V15 = 719*0.050 = 35.95 kg
Vf=Vi(1+*T)
Vf= 50litre*(1+0.000960*(-25-15)) = 48.08 litre = 0.04808 m^3
b)
-25 = m/ V-25 = 35.95/0.04808 = 747.7 kg/m^3
c)
m = m-25 – m15 = V.(-25 - 15) = 0.050*(747.7-719.0) = 1.435 kg
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