l Course Contents Correction Exam 2 (due Thursday, 3/23 at 11:59pM) Question 6 T

Question

l Course Contents Correction Exam 2 (due Thursday, 3/23 at 11:59pM) Question 6 Timer Notes Evaluate & Feedback Print A patient is having a magnetic resonance imaging scan (an MRI) and has neglected to remove a circular, metallic bracelet. The resistance of the bracelet is 0.0171 2. The magnetic field within t MRI's solenoid is per lar to the opening of his the scan, the magnetic field decreases from 1.35 T to 0.43 T in 0,900 seconds. If the magnitude of the average induced current in the bracelet during this time interval is 0.2255 A, what is the area of the opening of the circular bracelet? Submit Answer Units required Tries 2/20 Previous Tries Doet d F

Explanation / Answer

lnduced current = induced emf / R

lnduced emf E = -A*dB/ dt

so, current l = (A*dB/ dt) / R

0.2255 = -A*(0.43 - 1.35) / 0.90*0.0171

Area of the bracelet is,

A = 0.00377 m^2

Related Questions

Navigate

• Browse (All)
• Browse L
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.