Answer to #12 please and thank you! un ave age force exerted on the water by the

Question

Answer to #12 please and thank you!

un ave age force exerted on the water by the blade, 20. mmt A student (m 63 kg) falls freely from rest and strikes the (empty of ground, During the collision with the ground, he comes to rest in a time The astronau of 0.040 The sion Dr average force exerted on him by the ground is +18 000 N. unit. where the upward direction is taken to be positive direction. From of +32 m/s. the what height did the student fall? Assume that the only force acting on him After the ga during the collision is that due to the ground. empty prop from the co *12. A golf ball strikes a hard, 45 m/s smooth floor at an angle of 30.09 and, 21. ssm A as the drawing shows, rebounds at 4900 m/s the same angle. The mass of the ball placed betv is 0.047 kg, and its speed is 45 m/s 1200 kg up 0.0 30. just before and after striking the floor. sion. What What is the magnitude of the impulse stage after 45 m/s applied to the golf ball by the floor? "22. (Hint: Note that only the vertical 5.30 m/s component of the ball's momentum Just after I changes during impact with the fioor and ignore the weighi of the ball. the side wa s13. An 85-kg jogger is heading due east at a speed of 2.0 m/s. A between th 55-kg jogger is heading 32 north of east at a speed of 3.0 m/s. Find the ity relative

Explanation / Answer

By momentum- impulse theorem

Impulse = change in momentum

along Horizontal direction ,the change in momentum is 45*sin(30) - 45*sin(30) = 0

along vertical direction

change in momentum is dp_y = 45*cos(30) + 45*cos(30) = 2*45*cos(30) = 77.94 Kg-m/sec

impulse = dp_y = 77.94 kg-m/sec

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