Hints 1-Calculate entropy of the mixture 2- calculate Cp 3- Finally integrate th

Question

Hints 1-Calculate entropy of the mixture

2- calculate Cp

3- Finally integrate the entropy change equation to find total entropy change.

4-Answr for both steps is -104j/k

4-Answr for both steps is -104j/k

42 moles of pure hydrogen gas and 17 moles of pure oxygen gas are first mixed at a constant temperature of 60°C and a constant pressure of 2 bar. The mixture is then cooled isobarically to a temperature of 25°C. Calculate the total entropy change for the process of mixing and cooling You can assume ideal mixture behaviour. Heat capacities for the gases are cP (H2) 29.2 J mol 1 K-1 and cP (O2) 29.7 J mol-1 K-1.

Explanation / Answer

Given that,

Volume of the pure hydrogen gas is, V1=42 moles

volume of the pure oxygen gas is, V2=17 moles

Temperature is Th=600 C=273+60=333 K

Pressure is P=2 mbar

Tc=250C=273+25=298 K

PV=nRT

n=(P(V1+V2)/(T1-T2))/(R)

n=(2 mbar*(42 moles+17 moles)/(333 K-298 K))/(8.314 J/(K. mol))

=567.7

DS=nRln(V2/V1)

     =(567.7)(8.314 J/(K. mol))ln(17 mole/42 mole)

     =-4270 J/K

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