Two large, parallel, metal plates carry opposite charges of equal magnitude. The

Question

Two large, parallel, metal plates carry opposite charges of equal magnitude. They are separated by a distance of 50.0 mm and the potential difference between them is 350 V What is the magnitude of the electric field (assumed to be uniform) in the region between the plates? E = _________ N/C What is the magnitude of the force this field exerts on a particle with a charge of 2.30 nC? F = ________________ N Use the results of part (b) to compute the work done by the field on the particle from the higher-potential plate to the lower, W = _______ J Compare the result of part (c) to the change of potential energy of the same charge, computed from the electric potential. Delta U = ______________

Explanation / Answer

a) V = E*d

E = V/d

= 350 / 0.05 = 7000 V/m

b) F = kq1q2 / r^2

= 9*10^9*2.3*10^-9*2.3*10^-9 / 0.05^2

= 1.9044*10^-5 N

c) work done = chane in PE

= F*r = 1.9044*10^-5*0.05 = 9.522*10^-7 J

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.