As shown in the figure below, object mi 65 kg starts at an initial height hi J 3

Question

As shown in the figure below, object mi 65 kg starts at an initial height hi J 345 m and speed v1r 4.00 m swings downward and strikes (in an elastic collision) object m2 4.60 kg which is initially at rest. Determine the follow ng Kay speed of m, just before the c m/s (b) velocity (magnitude and direction) of each ball just after the collision (Assume the positive direction is toward the right. Indicate the direction with the sign of your answer.) m/s (m m/s (m2) Kc) height to which each ball swings after the collision (ignoring alr resistance) m (m1) m (m2) Supporting Materials physical Constants

Explanation / Answer

Size of initial momentum = 0.00467x(619) = 2.8907 kg-m/s
Size of final momentum = 0.074(17) + 0.00467(V) = 2.8907 kg-m/s
2.8907 - 1.258 = 0.00467V
V = 349.61 m/s .............................................ANS (a)

(b) => less than the initial KE

comparing before and after KE's shows the amt of "lost KE" due to frictional forces of collision
KE initial = (0.5)(0.00467)(619)² = 894.68 J
KE final = 0.5x(0.00467)(349.61)² + 0.5(0.074)(17)² = 296.09 J
"lost KE" = 894.68 - 296.06 = 598.60 J

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.