A factory worker pushes a 25.0-kg crate a distance of 4.1 m along a level floor

Question

A factory worker pushes a 25.0-kg crate a distance of 4.1 m along a level floor at constant velocity by pushing horizontally on it. The coefficient of kinetic friction between the crate and the floor is 0.30. Suppose the worker pushes downward at and angle of 32° below horizontal.

If work is Force x Distance, where does 371 J come from?

A factory worker pushes a 25.0-kg crate a distance of 4.1 m along a level floor at constant velocity by pushing horizontally on it. The coefficient of kinetic friction between the crate and the floor is 0.30. Suppose the worker pushes downward at and angle of 32° below horizontal. (d) What agnitude of force ITIust the worker apply 107 N 106.67 (b) How much work is done on the crate by this force? 437.33 x 371 1 (c) How much work is done on the crate by friction?

Explanation / Answer

By definition work done W = F*s cos theta = 106.67*4.1 cos 32 = 370.89123 = 371 J

work done by the friction force is also same as the workdone on the crate as long as it is moving with constnat velcoty

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