1. Find the tension in the rope. 2. As soon as the speed of 8 m/s is reached, th

Question

1. Find the tension in the rope. 2. As soon as the speed of 8 m/s is reached, the friend jumps out of the raft. The drag force on the raft remains constant, and tension in the rope is constant. What is the new acceleration? A person riding a jet-ski is pulling their friend around a lake. The friend is sitting in a raft that is connected to the jet ski with a long rope The jet-skier rides in astraight line, starting from rest, accelerating up to a speed of 8.00 m/s in 3 50seeends. (The rope stays taut and acceleration is constant.) The raft experiences a constant 230.00 Nof drag as it is pulled along the surface of the water. The friend has a mass of 70.0 kg and the raft has a mass of 35.0 kg.

Explanation / Answer

Here acceleration of both jet-ski and raft is same as rope is taut.

acceleration , a = 8/3.5 = 2.29 m/s2

Net force on the raft , F = ma

where m= 70+ 35 = 105 kg

net force F= 105* 2.29 = 240.45 N

Drag force f is in opposite direction

a) the tension T in the string

T= F+ f = 240.45+ 230 = 470.45 N

b) assuming the force with which jet-ski is pulling thr raft remains constant

T will be same

Acceleration , a' = F/m' = 240.45/ 35 = 6.87 m/s2

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