I can get the table at the top done by myself but I\'m stuck on a and b on the b

Question

I can get the table at the top done by myself but I'm stuck on a and b on the bottom.

Energy and Momentum (1) The two masses stick together after they collide and a1) the thick horizontal line is a rough surface with friction. For the two-mass system, when is momentum or mechanical energy conserved (unchanged)? For u20 example, is the total momentum the same in picture #1 as in picture #2? Put your answer in the box with the #3) Situations p conserve Emech conserved? #1 and #2 #2 and #3 Note: Emech K+u #1 and #3 Let mi 1.0 m2- 2.0 kg and the initial speed of my be 6.0 m/s. After they (The collide, they kg, onto the friction-surface. friction force come to a halt 3.0 s after m2 first slides region, so you changes as m of the boxes slide into the friction can't assume constant friction force.) a) What was the speed of the masses just after the collision? What was the average force exerted on the two-mass system by the b) surface as the masses came to a halt?

Explanation / Answer

a) It is an inelastic collision ,

By conservation of momentum :

Initial momentum = Final momentum

m1v1= (m1+m2) vf

Final velocity vf= m1v1/(m1+m2)

vf= (1×6)/(1+2) = 2m/s

b) we know that ,

Momentum = Favgt

Favg = P/t = 6 kg.m/s. ÷ 3s = 2 N

  

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