1.Two capacitors of 5.00 mF and 10.00 mF are connected in series. The combinatio
ID: 1595617 • Letter: 1
Question
1.Two capacitors of 5.00 mF and 10.00 mF are connected in series. The combination is then connected in parallel with a 10.0 V battery and a 10 mF capacitor. (a) what is the equivalent capacitance? (b) what is the charge on each capacitor? (c) what is the voltage drop on each capacitor?
2. A 1.0 mF capacitor with an initial stored energy of 0.50 J is discharged through a 1.0 MW resistor. (a) what is the initial charge on the capacitor? (b) what is the current through the resistor when the discharge starts? (c) determine Vc , the potential difference across the capacitor, VR, the potential difference across the resistor, as function of time. (d) express the production rate of thermal energy in the resistor as a function of time.
Explanation / Answer
1. C1 = 5.00 mF, C2 = 10.00 mF, C3 = 10.00 mF and v = 10.0 V
The C1 and C2 are connected to series
Cs = C1*C2/C1+C2
= 5*10/5+10
= 3.34 mF
And the C3 is connected to the parallel
Ceq = 3.34+10.0
= 13.34 mF
(a) the equivalent capacitance is
Ceq = 13.34 mF
(b) The charge on C1 is
q = C1*v
= 5.00*10^-3 * 10.0
= 5*10^-2 C
The charge on C2 is
q = C2*v
= 10.0*10^-3 * 10.0
= 0.10 C
The charge on C3 is
q = C3*v
= 10.0*10^-3 * 10.0
= 0.10 C
(c) the voltage drop on each capacitor is
v = q/Ceq
v1 = 0.05/13.34*10^-3 = 3.74 v
v2 = 0.10/13.34*10^-3 = 7.49 v
v3 = 0.10/13.34*10^-3 = 7.49 v
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