A toboggan approaches a snowy hill moving at 13.3 m/s . The coefficients of stat
ID: 1595201 • Letter: A
Question
A toboggan approaches a snowy hill moving at 13.3 m/s . The coefficients of static and kinetic friction between the snow and the toboggan are 0.430 and 0.310, respectively, and the hill slopes upward at 45.0 above the horizontal. Part A Find the acceleration of the toboggan as it is going up the hill. Assume +x axis directed up the hill. ax = m/s2 SubmitMy AnswersGive Up Part B Find the acceleration of the toboggan after it has reached its highest point and is sliding down the hill. Assume +x axis directed up the hill.
Explanation / Answer
force acting on toboggan while going upwards (along - x )= mu*mgcos(theta) + mgsin(theta)
acceleration = mu*gcos(45) + gsin(45) = -9.08709995571 m/s2
negative as acceleration is downhill
as it reaches highest point
force downhill = mgsin(45)
force uphill = mu*mgcos(45)
acceleration = gsin(45)- mu*gcos(45) = -3.9539 m/s2 ax
since it is coming positive means
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