Problem 21.07 A 19-cm-diameter circular loop of wire is placed in a 0.85-T magne
ID: 1595129 • Letter: P
Question
Problem 21.07 A 19-cm-diameter circular loop of wire is placed in a 0.85-T magnetic field Part A When the plane of the loop is perpendicular to the field lines, what is the magnetic flux through the loop? Express your answer to two significant figures and include the appropriate units. Value Units Submit My Answers Give Up incorrect; Try Again; 4 attempts remaining Part B The plane of the loop is rotated until it makes a 37 angle with the field lines. What is the angle in the equation PB BA cos 0 for this situation? Express your answer using two significant figures AEG Submit My Answers Give UpExplanation / Answer
flux is BAcos(theta) where theta is the angle between the mag field vector and the normal (perpendicular) to the plane of the circle
a)
theta=0
so
flux = BA = 0.85T*(pi*0.09m(^2) =. 24 wb
b)
theta is the angle between the perpendicular to the loop, so theta = 90-37 = 53
c)
flux = BA cos53,
==0.14wb
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