A car is traveling around a horizontal circular track with radius r = 230 m as s

Question

A car is traveling around a horizontal circular track with radius r = 230 m as shown. It takes the car t = 53 s to go around the track once. The angle A = 35° above the x axis, and the angle B = 59° below the x axis.

1)What is the magnitude of the car’s acceleration?

2)What is the x component of the car’s velocity when it is at point A

3)What is the y component of the car’s velocity when it is at point A

4)What is the x component of the car’s acceleration when it is at point B

5)What is the y component of the car’s acceleration when it is at point B

Explanation / Answer

1) V= 2PIE R /t

= 27.25 m/s

a)centripetal = v2 / r

= 3.23 m/s2

b)when at point A , Vx = - v sin 35

= -15.63 m/s

c) Vy = v cos 35

= 22.32m/s

d) at point B , a)x = - Vb2/r * cos 59

* calculate

e)a)y = Vb2/r sin 59

* calculate

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