A tin can is filled with water to a depth of 44 c m . A hole 18 c m above the bo

Question

A tin can is filled with water to a depth of 44 cm . A hole 18 cm above the bottom of the can produces a stream of water that is directed at an angle of 39 above the horizontal. Part A Find the range of this stream of water. Express your answer using two significant figures. Part B Find the maximum height of this stream of water. Express your answer using two significant figures. A tin can is filled with water to a depth of 44 cm . A hole 18 cm above the bottom of the can produces a stream of water that is directed at an angle of 39 above the horizontal. Part A Find the range of this stream of water. Express your answer using two significant figures. Part B Find the maximum height of this stream of water. Express your answer using two significant figures. A tin can is filled with water to a depth of 44 cm . A hole 18 cm above the bottom of the can produces a stream of water that is directed at an angle of 39 above the horizontal. A tin can is filled with water to a depth of 44 cm . A hole 18 cm above the bottom of the can produces a stream of water that is directed at an angle of 39 above the horizontal. A tin can is filled with water to a depth of 44 cm . A hole 18 cm above the bottom of the can produces a stream of water that is directed at an angle of 39 above the horizontal. Part A Find the range of this stream of water. Express your answer using two significant figures. Part B Find the maximum height of this stream of water. Express your answer using two significant figures. Part A Find the range of this stream of water. Express your answer using two significant figures. Part B Find the maximum height of this stream of water. Express your answer using two significant figures. Part A Find the range of this stream of water. Express your answer using two significant figures. Part B Find the maximum height of this stream of water. Express your answer using two significant figures. Part B Find the maximum height of this stream of water. Express your answer using two significant figures.

Explanation / Answer

We will calculate the velocity of the water using Bernoulli's equation :

Po + gh + (1/2)v² = constant

Po = Pressure outside of can
= density of water
g = gravity (-9.8m/s²)
h = depth of fluid
v = velocity of fluid

If we take those variables at any point in the fluid, the equation will always equal a constant, meaning we can take two points in the fluid and set them equal to each other.
Lets take one point at the fluid's surface,

Po = Patm
= 1 kg/m^3
g = -9.8m/s²
h = 0.0 m
v = 0 m/s

The other point is at the hole.

Po = Patm
= 1 kg/m^3
g = -9.8m/s²
h = 0.26 m
v = ???

We know that the hole is at 26cm below the surface, but we need to calculate the velocity. We can now take both sets of variables, plug them into bernoulli's and set them equal to one another (left is surface, right is hole).

Po + gh + (1/2)v² = Po + gh + (1/2)v²

The Po are the same so they cancel, the (1/2)v² on the left is 0 because v = 0 m/s, and the gh on the left can go away because the h is at a depth of 0.0 cm.

0 = gh + (1/2)v²

Move the equation around and take out the since it's a common factor.

(1/2)v² = -gh
(1/2)v² = -gh
v² = -2gh
v = sqrt(-2gh)
v = sqrt(2*9.8*0.26) = 2.2574 m/s

As for the range questions, we can solve them using kinematics equations.
The range equation will be especially useful for part "a":
range = (v²/g) sin(2)

R = 2.2574*2.2574/9.8 * sin78 = 0.5086 m or 50.86 cm……….Ans.

For part B, we can use the ymax equation:
ymax = v²sin²() / (2g)

Ymax = 2.2574*2.2574/2*9.8 * sin239 = 0.1029 m

Total height = 10.29 cm + 18 cm = 28.29 cm……….Ans.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.