In this example we will see how to handle the case of an object resting on an in

Question

In this example we will see how to handle the case of an object resting on an inclined plane. A car with a weight of 1.76×104N rests on the ramp of a trailer (Figure 1) . The car’s brakes and transmission lock are released; only the cable prevents the car from rolling backward off the trailer. The ramp makes an angle of 26.0 with the horizontal. Find the tension in the cable and the force with which the ramp pushes on the car’s tires.What ramp angle would be needed in order for the cable tension to equal one-third of the car’s weight?

Explanation / Answer

Tension in the cable T= F sin theta (F= weight of car)

And the normal reaction force on tyres of car

R = F cos theta

So T = 1.76*10^4 × sin 26

= 7.71*10^3 N

R = 1.76*10^4 * cos 26 = 1.58*10^4 N

B) theta for T = 1/3 × F

F / 3 F = sin theta

Theta = 19.47 °

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