AM Inbox (40) ktormo00 x f Facebook x M Subscriptions YouT x Kurt G1 Mastering P

Question

AM Inbox (40) ktormo00 x f Facebook x M Subscriptions YouT x Kurt G1 Mastering Physics: As x MasteringPhysics: Ch x C fi https: masteringphysics.com/myct/itemView offset next&assignmentProblemID; 7968089 Apps M UCR M Pcc f Facebook o My subscription Twitter Bb Welcome, Kurt B LancerPoint Log NBA com E LeBrown James D WeBWork MA. Slicethepie e Warner Ca... Electronics, Car. r bookmarks Signed in as Kurt Tomongin Hep l Close PHYS040 (02 Ch 19 HW Proble 19.48 previous l 3 of 10 l next Problem 19.48 Part A A nuclear power plant generates 3000 MW of heat energy from nuclear reactions in the maximum possible thermal efficiency of the power plant? reactors core. This energy is used to boil water and produce high-pressure steam at 280 Express your answer using two significant figures. o C. The steam spins a turbine, which produces 1100 MW of electric power, then the steam is condensed and the water is cooled to 25 C before starting the cycle again. Subm My Answers Give Up Part B What is the plant's actual efficiency? Express your answer using two significant figures. Subm swers Give Up Part C cooling water from a river flows through the condenser (he low-temperature heat exchanger) at the rate of 1.2 x 105 L/h (w 30 million gallons per hour). lf the river water enters the condenser at 18 C. what is its exit temperature? Express your answer using two significant figures. Subm swers Give Up Provide Feedback Continue 12:02 AM PSI Pr 2/14/2016

Explanation / Answer

a)

Carnot efficiency = 1 - Tc/Th

(25 + 273) / (280 + 273)

1- (298K/553K) = 0 .461

b)

rate of Wout = 1100 MW = 11 * 10^8 J/s

Rate of Qh = 3000MW = 3 * 10^9 J/s

Efficiency = (11*10^8J/s)/(3*10^9J/s )= 0.36

c)

rate of work out = rateQh-rateQc

(11.0*10^8)=(3*10^9J/s)-Qc

Qc= 1.9 * 10^9 J/s

so

1.9 *10^9J/s * 3600s/1.2*10^8kg = 57000J/kg

Q=mcT 57000 = 1kg*4160T

T=13.70degrees C

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.