Julie throws a ball to her friend Sarah. The ball leaves Julie\'s hand a distanc

Question

Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial speed of 12 m/s at an angle 48 degrees; with respect to the horizontal. Sarah catches the ball 1.5 meters above the ground.

1) What is the horizontal component of the ball’s velocity right before Sarah catches it?

8.03m/s

2) What is the vertical component of the ball’s velocity right before Sarah catches it?

-8.92m/s

3) What is the time the ball is in the air?

1.82s

4) What is the distance between the two girls?

14.61m

5) After catching the ball, Sarah throws it back to Julie. However, Sarah throws it too hard so it is over Julie's head when it reaches Julie's horizontal position. Assume the ball leaves Sarah's hand a distance 1.5 meters above the ground, reaches a maximum height of 7 m above the ground, and takes 1.46 s to get directly over Julie's head.

5) After catching the ball, Sarah throws it back to Julie. However, Sarah throws it too hard so it is over Julie's head when it reaches Julie's horizontal position. Assume the ball leaves Sarah's hand a distance 1.5 meters above the ground, reaches a maximum height of 7 m above the ground, and takes 1.46 s to get directly over Julie's head.

6)

How high above the ground will the ball be when it gets to Julie?

i need the answer for q6

Explanation / Answer

h = 1.5+Vyt-4.9t^2

Vy is the velocity from the hand of sarah. (I have taken from julie hence the answer was wrong)

h = 7-1.5 = Vy^2/2g

Vy = 10.382 m/sec

h= 1.5+ 10.382 * 1.46 -4.9*1.46*1.46

6.21 m

edited answer please rate me

Related Questions

Navigate

• Browse (All)
• Browse J
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.