An electron is released from rest at the negative plate of a parallel plate capa

Question

An electron is released from rest at the negative plate of a parallel plate capacitor. If the distance between the plates is 5 mm and the potential difference across the plates is 5 V, with what velocity does the electron hit the positive plate? (me = 9.1 x 10-31 kg, = 1.6 x 10-19 C. (Give your answer in Mm/s, 1 Mm/s= A rod of 2.0-m length and a square (2.0 mm x 2.0 mm) cross section is made of a material with a resistivity of 6.0 x 10-8 Ohm m. If a potential difference of 0.50 V is placed across the ends of the rod, at what rate is heat generated in the rod?

Explanation / Answer

V = potential difference = 5 Volts

qe = charge = 1.6 x 10-19 C

v = speed

Using conservation of energy

Kinetic energy of electron = electric potential energy

(0.5) me v2 = qeV

(0.5) (9.1 x 10-31) v2 = (1.6 x 10-19 ) (5)

v = 1.33 x 106 m/s

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