Solve for Parts A and B (20%) Problem 1: Consider a skier heading down a 7.5o sl

Question

Solve for Parts A and B

(20%) Problem 1: Consider a skier heading down a 7.5o slope. Assume the coefficient of friction for waxed wood on wet snow is Hk 0.10 and use a coordinate system in which down the slope is positive. Randomized Variables 75 A 50% Part (a) Calculate the acceleration of the skier in m/s Grade Summary Deductions Potential 100% Submissions sino cos tano D 7 8 9 Attempts remaining: 5 (10% per attempt) cotano asi acos0 4 5 6 detailed view acotano sinh0 1 2 3 atan cosh0 tanh() cotanh0 Degrees O Radians Feedback Submit Hint I give up! Hints 5 deduction per hint. Hints remaining 4 Feedback: 3% deduction per feedback A 50% Part (b) Find the angle of the slope down which this skier could coast at a constant velocity in degrees

Explanation / Answer

uk = 0.10
= 7.5o

Fnet = m*a
m*g sin() - uk*m*g*cos() = m*a
a = 9.8 * sin(7.5) - 0.1 * 9.8 * cos(7.5)
a = 0.31 m/s^2
Acceleration of the skier, a = 0.31 m/s^2

(b)
If the skier need to coast at constsnt velocity, Acceleration = 0
m*g sin() - uk*m*g*cos() = 0
m*g*sin() = uk *m* g * cos()
tan() = 0.1
= 5.7 o
Angle of the slope down, = 5.7 o

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