2.60-kg block starts from test at the top of a 30.0^4 incline and slides a dista
ID: 1591548 • Letter: 2
Question
2.60-kg block starts from test at the top of a 30.0^4 incline and slides a distance of 1.90 m down the Incline in 2.00 s. Find the magnitude of the acceleration of the block. Find the coefficient of kinetic friction between block and plane. Find the friction force acting on the block. Draw a careful fire-body diagram of the forces acting on the block. Determine the components of the vectors in a coordinate system parallel and perpendicular to the incline. Find the speed of the block after it has slid 1.90 m.Explanation / Answer
b)Balancing force equation along the incline
ma=mgsin30- umgcos30
a=gsin30-ugcos30
0.95=9.8*0.5 - u*9.8* 0.866
0.95=4.9 - 8.49u
u=[4.9-0.95]/8.49=3.95/8.49
u = 0.465 ......coefficient of kinetic friction
friction force= umgcos30= 0.465*2.6*9.8*0.866 =10.26 N
Direction is up the incline,
d) v=u+at= 0+ 0.95*2 = 1.9 m/s
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