UUnless otherwise stated, all objects are located near the Earth\'s surface, whe
ID: 1590608 • Letter: U
Question
UUnless otherwise stated, all objects are located near the Earth's surface, where g = 9.80 m/s2 . An Atwood machine (see the figure (Figure 1) ) has suspended masses of 0.30 kg and 0.15 kg . Part A Under ideal conditions, what will be the magnitude of the acceleration of the smaller mass? Express your answer using two significant figures. Part B What will be the direction of the acceleration of the smaller mass?
Unless otherwise stated, all objects are located near the Earth's surface, where g = 9.80 m/s2 .
Assuming ideal frictionless conditions for the apparatus shown in the figure (Figure 1) , what is the acceleration of the system in the following conditions.
Part A
m1 = 0.30 kg , m2 = 0.55 kg , and m3 = 0.23 kg .
Find the magnitude of the acceleration.
Part C
m1 = 0.31 kg , m2 = 0.11 kg , and m3 = 0.46 kg .
Find the magnitude of the acceleration.
Unless otherwise stated, all objects are located near the Earth's surface, where g = 9.80 m/s2 .
Assuming ideal frictionless conditions for the apparatus shown in the figure (Figure 1) , what is the acceleration of the system in the following conditions.
Part A
m1 = 0.30 kg , m2 = 0.55 kg , and m3 = 0.23 kg .
Find the magnitude of the acceleration.
Part C
m1 = 0.31 kg , m2 = 0.11 kg , and m3 = 0.46 kg .
Find the magnitude of the acceleration.
Explanation / Answer
apply newton's second law to each mass, that means identifying all the forces acting on the masss
call T1 the tension in the string to the left and T2 the tension in the string on the right
T1 - m1 g = m1a (assume m1 accelerates up)
for m2: T2-m2g = - m2a (we assume m2 accelerates down)
T2 - T1 = m3a
T2-T1 = m2(g-a) - m1(g+a) = m3 a
a =(m2-m1)g/(m1+m2+m3)
a=(0.55-0.3)*9.8/(0.55+0.3+0.23)
=0.23*9.8m/s2
=2.3m/s2
PARTC)
a=(0.11-0.31)*9.8/(0.31+0.11+0.46)
=-0.22*9.8m/s2
=-2.2m/s2
m1>m2 system moves towards left[
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