You\'re 1.44 m from a charge distribution that is well under 1 cm in size. You m

Question

You're 1.44 m from a charge distribution that is well under 1 cm in size. You measure an electric field strength of 296 N/C due to this distribution. You then move to a distance of 2.16 m from the distribution, where you measure a field strength of 87.7 N/C.

Part A:

Determine instead how the field decreases with distance.

Part B

What's the net charge of the distribution?

o Field falls off like r3 for ra, so the charge distribution must be a monopole. o Field falls off like r3 for ra, so the charge distribution must be a dipole. o Field falls off like r2 for ra, so the charge distribution must be a monopole. o Field falls off like r2 for ra, so the charge distribution must be a dipole.

Explanation / Answer

E' / E = (r' / r)^a

(296/87.7) = (2.16/1.44)^a

a = - 3

so field falls off lime r^-3 for r >>a, so charge distribution must be dipole.

B) E = kQ / r^3

296 = ( 9 x 10^9 x Q ) / 1.44^3

Q = 9.82 x 10^-8 C

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