Solve for Part A. (20%) Problem 2: Suppose two children push horizontally, but i

Question

Solve for Part A.

(20%) Problem 2: Suppose two children push horizontally, but in exactly opposite directions, on a third child in a sled. The first kinetic friction is 5.5 child exerts a force of 75 N, the second a force of 98 N, and the mass of the third child plus sled is 21.5 N, kg Randomized variables fr 75 N 98 f3 5.5 N m 21.5 kg A 100% Part (a) Using a coordinate system where the second child is pushing in the positive direction, calculate the acceleration in m/s Grade Summary Deductions Potential 100% Submissions sino coso tano D 7 8 9 HOME Attempts remaining: 5 (10% per attempt) acos0 cotano asin 4 5 6 detailed view 1 2 3 atan acotano sinh0 cosh0 tanho cotanh0 Degrees O Radians Hint Feedback Submit I give up! Hints 5% deduction per hint. Hints remaining 5 Feedback 3% deduction per feedback.

Explanation / Answer

Solution:

Here the 2nd child 's force = F2 = +98 N since it is in positive direction.

F1= -75 N , since the 1st & 2nd child are pushing in opposite directions.

Friction = f = 5.5 N

Net force = F1+F2 = (-75 + 98) -5.5 = 23 - 5.5 N = 17.5N

Acceleration = net force / mass = 17.5 / 21.5 = 0.81 m/s2

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