PART A - In the drawing above, E = 4.0N/C and d = 1.5m. Calculate the work done

Question

PART A - In the drawing above, E = 4.0N/C and d = 1.5m. Calculate the work done by the electric field in moving a +5.0x10-9C charge from A to B. Be sure to include - sign if your answer is negative. Your answer needs to be in J but you don't need to enter the unit in your answer for this question.

PART B - In the situation in diagram c above, calculate the potential energy difference between the +5.0x10-9C charge at B and at A. Be sure to include - sign if your answer is negative. Your answer needs to be in J but you don't need to enter the unit in your answer for this question.

PART C - For the situation in diagram c above, calculate the potential difference between A and B. Be sure to include - sign if your answer is negative. Your answer needs to be in V but you don't need to enter the unit in your answer for this question

Explanation / Answer

PART-A:

The work done = F*d = E*q*d

                               = 4 X (5*10-9) X 1.5

                              = 3*10-8 J

PART-B:

PE = q*V (positive)

           = (5*10-9) X (3*10-8 )

         = 1.5*10-16J-C

PART-C:

V = -W/q = 3*10-8 /5*10-9= 6 V.

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