PART A - In the drawing above, E = 4.0N/C and d = 1.5m. Calculate the work done

Question

PART A - In the drawing above, E = 4.0N/C and d = 1.5m. Calculate the work done by the electric field in moving a +5.0x10-9C charge from A to B. Be sure to include - sign if your answer is negative. Your answer needs to be in J but you don't need to enter the unit in your answer for this question

PART B - In the situation in diagram a above, calculate the potential energy difference between the +5.0x10-9C charge at B and at A. Be sure to include - sign if your answer is negative. Your answer needs to be in J but you don't need to enter the unit in your answer for this question.

PART C - For the situation in diagram a above, calculate the potential difference between A and B. Be sure to include - sign if your answer is negative. Your answer needs to be in V but you don't need to enter the unit in your answer for this question.

Explanation / Answer

Part A

We know that Work W= qE.d

W = +5.0x10-9C* 4.0N/C* 1.5m = 3.0 x 10-8 J...........Ans.

Part B

We know that change in potential energy = work done

hence it is also 3.0 x 10-8 J...........Ans.

Part C

Potential difference

V = W/Q = 3.0 x 10-8 J / 5x10-9 = 6.0 V ..........Ans.

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