A physics book slides off a horizontal table top with a speed of 1.60 m/s . It s

Question

A physics book slides off a horizontal table top with a speed of 1.60 m/s . It strikes the floor after a time of 0.410 s . Ignore air resistance.

Part A

Find the height of the table top above the floor.

Express your answer with the appropriate units.

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Part B

Find the horizontal distance from the edge of the table to the point where the book strikes the floor.

Express your answer with the appropriate units.

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Part C

Find the magnitude of the horizontal component of the book's velocity just before the book reaches the floor.

Express your answer with the appropriate units.

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Part D

Find the magnitude of the vertical component of the book's velocity just before the book reaches the floor.

Express your answer with the appropriate units.

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Part E

Find the magnitude of the book's velocity just before the book reaches the floor.

Express your answer with the appropriate units.

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Part F

Find the direction of the book's velocity just before the book reaches the floor.

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Explanation / Answer

A)

along vertical voy = 0

acceleration ay = -g

time t =0.41 s

y =voy*t + 0.5*g*t^2

-h = 0 - 0.5*9.8*0.41^2

h = 0.824 m

B)

X = vox*t = 1.6*0.41 = 0.656 m

C)

along horizantal ax = 0

vx = vox + ax*t

vx = vox = 1.6 m/s

(d)

vy = voy + ay*t

vy = 0 - 9.8*0.41 = -4.018 m/s

magnitude vy = 4.018 m/s

(e)

v = sqrt(vx^2+vy62) = sqrt(1.6^2 + 4.018^2) = 4.32 m/s

(f)

direction = tan^-1(vy/vx) = 68.3

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