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two resistors are connected in parallel to a V=6.25 V source. Input an expressio

ID: 1588364 • Letter: T

Question

two resistors are connected in parallel to a V=6.25 V source. Input an expression for the amount of charge q which passes through the circuit

(20%) Problem 1: Two resistors are connected in parallel ( R1 = 7.5 , R2 = 5.2 ) to a V= 6.25 V source 33% Part (a) Input an expression for the amount of charge q which passes through the circuit every second? Grade Summary Deductions Potential 0% 100% 789 Submissions Attempts remaining: 3 (5% per attempt) detailed view 0 BACKSPACE DELCLEAR Submit Hint I give up! Hints: 3% deduction per hint. Hints remaining: 6 Feedback: 3% deduction per feedback là 33% Part (b) What is the charge per second in C? 33% Part (c) How much power is dissipated in the circuit in W?

Explanation / Answer


In parallel combination


1/Rtot = 1/R1 + 1/R2

Rtot = (R1*R2)/(R1+R2)


a) charge q passing everty second = V/Rtot = V*(R1+R2)/(R1*R2)


b) charge persec q = (6.25*(7.5+5.2))/(7.5*5.2) = 2.04 C

c) P = V*q = 6.25*2.04 = 12.75 W