A parallel plate capacitor with plate separation d is connected to a battery. Th
ID: 1587966 • Letter: A
Question
A parallel plate capacitor with plate separation d is connected to a battery. The capacitor is fully charged to Q Coulombs and a voltage of V. (C is the capacitance and U is the stored energy.) Answer the following questions regarding the capacitor charged by a battery. For each statement below, select True or False.
True False After being disconnected from the battery, increasing d increases V.
True False After being disconnected from the battery, inserting a dielectric with will decrease V.
True False With the capacitor connected to the battery, decreasing d increases C.
True False After being disconnected from the battery, inserting a dielectric with will increase C.
True False After being disconnected from the battery, inserting a dielectric with will decrease U.
True False After being disconnected from the battery, decreasing d increases U.
Explanation / Answer
Formula Used:
1. Q = CV, 2. C =e0*A/d 3. e0 = k*er 4. U = 0.5*C*V^2
A. TRUE.
Reason: Now if we increase d it will decrease C by formula 2, and if C decrease then V increases by formula 1
B. FALSE
Reason: Inserting a dielctric will increase C as C is proportional to dielectric constant by formula 3, and if C increase then V decreases by formula 1.
C. TRUE
The Voltage is constant since battery is connected so decreasing d will increase C by formula 2.
D. TRUE
Inserting a dielctric will increase C as C is proportional to dielectric constant by formula 3.
E. FALSE
Inserting a dielectric will increase C and Cis proportional to U so U will increase if C increases by formula 4.
F. TRUE
Decreasong d will increase C by formula 2, and increasing C will increase U by formula 4.
Comment Below if you have any doubt.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.