A 42 inch. vertical jump consists of two parts. The first stage is the quick acc

Question

A 42 inch. vertical jump consists of two parts. The first stage is the quick acceleration of the center of mass from a crouching to a standing position. The center of mass rises by 20 cm in this stage. In the second stage, the player's feet leave the floor and the center of mass rises by 42 in. under the influence of gravity alone. A.) What is the player's velocity just as his feet leave the floor? B.) What is the average acceleration during the first phase of the jump? C.) What is the average acceleration during the second phase of the jump? D.) If the player is 185 lb., what force do his legs need to exert, to execute this jump?

Explanation / Answer

A) Apply v2=u2+2as

0=u2 - 2*32*(42/12)

players velocity(u)= 14.97 ft/s

B) Need the time taken to stand.

C) average acceleration= gravitational acceleration= 32 feets per second

D)Need data for part B)

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